64x^2+32x-45=0

Solution for 64x^2+32x-45=0 equation:

64x^2+32x-45=0

a = 64; b = 32; c = -45;
Δ = b2-4ac
Δ = 322-4·64·(-45)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-112}{2*64}=\frac{-144}{128}
=-1+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+112}{2*64}=\frac{80}{128}
=5/8
$